Try: \( \frac{32 + x}{60} = \frac{66}{100} = \frac{33}{50} \Rightarrow 32 + x = \frac{33}{50} \times 60 = 39.6 \)
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- But since number of users is integer, \( 32 + x \) must be integer, so 39.6 must be rounded — but 66% of 60 is known to be 39.6 only if non-integer, which is invalid. Recheck: 66% of 60 is \( \frac{2}{3} \times 60 = 40 \) only if exact — but 66% = 33/50, so:
- + x = \frac{33}{50} \times 60 = 39.6
- Contradiction. Instead, assume reported rate is approximate, but in math olympiad context, expect exact fraction:
- But 39.6 is not integer — so likely the 66% is exact, hence total successes = \( 0.66 \times 60 = 39.6 \) — impossible.
- Wait — perhaps use fraction:
- \( 66\% = \frac{33}{50} \), but 50 does not divide 60.
