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Dimensions are 10 meters by 24 meters.
#### 10 meters by 24 meters
A ball is thrown upwards with an initial velocity of 20 m/s from a height of 50 meters. Using the equation \( h(t) = -5t^2 + 20t + 50 \), where \( h \) is the height in meters and \( t \) is the time in seconds, find the time when the ball hits the ground.
Set \( h(t) = 0 \):
\( -5t^2 + 20t + 50 = 0 \)
Divide the entire equation by -5:
\( t^2 - 4t - 10 = 0 \)
Use the quadratic formula: \( t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
Here, \( a = 1, b = -4, c = -10 \)
\( t = \frac{4 \pm \sqrt{16 + 40}}{2} \)