Their squares sum to \( (n - 1)^2 + n^2 + (n + 1)^2 = 365 \).
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- The area of the circle is \( \pi r^2 = 3.14 \times 5^2 = 3.14 \times 25 = 78.5 \).
- The sum of the squares of three consecutive integers is 365. What is the middle integer?
- Let the integers be \( n - 1, n, n + 1 \).
- This expands to \( n^2 - 2n + 1 + n^2 + n^2 + 2n + 1 = 365 \).
- Simplifying, \( 3n^2 + 2 = 365 \) leads to \( 3n^2 = 363 \).
- Thus, \( n^2 = 121 \), so \( n = 11 \) (since \( n \) is an integer).
