The groove is 1 cm wide and concentric, effectively reducing the radius of the remaining material to $ 5 - 1 = 4 $ cm. The area of the reduced circle (remaining material) is:

February 22, 2026

$The groove is 1 cm wide and concentric, effectively reducing the radius of the remaining material to $ 5 - 1 = 4 $ cm. The area of the reduced circle (remaining material) is:$

The original area of the circular microfossil is calculated using the formula for the area of a circle:
where $ r = 5 $ cm. Thus, the original area is:
A = \pi (5)^2 = 25\pi \text{ square centimeters.}
A_{\text{remaining}} = \pi (4)^2 = 16\pi \text{ square centimeters.}
Therefore, the area of the remaining microfossil material is:
\boxed{16\pi}

The groove is 1 cm wide and concentric, effectively reducing the radius of the remaining material to \( 5 - 1 = 4 \) cm. The area of the reduced circle (remaining material) is:

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