r^2 = \frac{100}{\sin(2\theta)}.

February 22, 2026

$r^2 = \frac{100}{\sin(2\theta)}.$

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We are given the polar equation:
We want to find the **maximum value of $r$** for which this equation has a solution.
Step 1: Solve for $r^2$:
Since $r^2 \geq 0$, we must have $\sin(2\theta) > 0$. The maximum value of $r^2$ occurs when $\sin(2\theta)$ is minimized (but still positive). The minimum positive value of $\sin(2\theta)$ is approaching 0, but we must consider the domain where the expression is defined and real.
However, to **maximize $r$**, we must **minimize the denominator** $\sin(2\theta)$, but not go below 0. So we consider the **maximum of $r^2$** under the constraint that $\sin(2\theta) > 0$. The maximum occurs when $\sin(2\theta)$ is at its **minimum positive value**, but that would make $r^2$ large — but we must find the **actual maximum possible finite value**.
Actually, the **maximum finite value of $r$** occurs when $\sin(2\theta)$ is at its **maximum**, because $r^2 = \frac{100}{\sin(2\theta)}$, and $\sin(2\theta) \leq 1$.

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