$$Question: How many numbers are in the list \( 3, 8, 13, \ldots, 98 \)?
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- $ k(2) = 2(2)^2 - 4(2) + m = 8 - 8 + m = m $
- Since $ h(2) = k(2) $, we have:
- m = 5
- Solution: The given sequence is an arithmetic sequence with the first term \( a = 3 \) and common difference \( d = 5 \). The general term of the sequence is given by:
- a_n = a + (n-1) \cdot d = 3 + (n-1) \cdot 5
- We need to find \( n \) such that \( a_n = 98 \):
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