Let $t = \sin 2x$, $0 < t \leq 1$ (since $x \in (0, \pi/2)\Rightarrow 2x \in (0, \pi)$, and $t = 1$ at $x = \pi/4$)

February 22, 2026

$Let $t = \sin 2x$, $0 < t \leq 1$ (since $x \in (0, \pi/2)\Rightarrow 2x \in (0, \pi)$, and $t = 1$ at $x = \pi/4$)$

Let \(t = \sin 2x\), \(0 < t \leq 1\) (since \(x \in (0, \pi/2)\Rightarrow 2x \in (0, \pi)\), and \(t = 1\) at \(x = \pi/4\))