If \( x = 3 \), then \( x - 1 = 2 > 0 \), valid.
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- So, \( x^2 - 1 = 2^3 = 8 \Rightarrow x^2 = 9 \Rightarrow x = \pm 3 \).
- Check domain: arguments of logs must be positive.
- If \( x = -3 \), then \( x - 1 = -4 < 0 \), invalid.
- Thus, the only solution is \( x = 3 \).
- A quadratic function passes through the points (1, 4), (2, 3), and (4, 15). What is the y-coefficient of the x-term in its standard form?
- Let the quadratic be \( f(x) = ax^2 + bx + c \).
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