For the 20th term, $a_{20} = 3(20) - 1 = 59$. However, the question asks for the count of terms, not the value. Since the sequence starts at $n = 1$ and ends at $n = 20$, there are $\boxed{20}$ numbers.Question: A square has a perimeter of $ 40 \, \text{cm} $. If each side is increased by $ 2 \, \text{cm} $, by how many square centimeters does the area increase?

For the 20th term, $a_{20} = 3(20) - 1 = 59$. However, the question asks for the count of terms, not the value. Since the sequence starts at $n = 1$ and ends at $n = 20$, there are $\boxed{20}$ numbers.Question: A square has a perimeter of $ 40 \, \text{cm} $. If each side is increased by $ 2 \, \text{cm} $, by how many square centimeters does the area increase?

["How Many Terms in the 20th Sequence? And How Has This Geometry Problem Evolved?", "For the 20th term of a sequence defined by $ a_n = 3n - 1 $, plugging in $ n = 20 $ shows that there are exactly $\boxed{20}$ numbers (terms) from $ n = 1 $ to $ n = 20 $. But geometry also inspires measurement—literally. Consider a square with a perimeter of $ 40 , \ ext{cm} $. Since a square has four equal sides, each side measures $ \frac{40}{4} = 10 , \ ext{cm} $. When each side is increased by $ 2 , \ ext{cm} $, the new side length becomes $ 10 + 2 = 12 , \ ext{cm} $.", "The original area is $ 10^2 = 100 , \ ext{cm}^2 $, and the new area is $ 12^2 = 144 , \ ext{cm}^2 $. The increase in area is $ 144 - 100 = 44 , \ ext{cm}^2 $. So, after enlarging each side, the area grows by $\boxed{44}$ square centimeters.", "This problem beautifully blends sequence counting with practical geometry—proving that even simple shapes follow precise mathematical rules. Whether exploring 20 terms or adjusting a square’s borders, every calculation tells a story of consistent growth."]

Related Articles

Trending Articles