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Area = 0.5 × base × height = 0.5 × 7 × 24 = 84 square cm.
A piece of wire 60 cm long is bent to form a rectangle. If the length is 5 cm more than the width, what are the dimensions of the rectangle?
Let the width be \( w \) cm. Then the length is \( w + 5 \) cm.
Perimeter = 2(length + width) = 2(w + w + 5) = 4w + 10.
Set 4w + 10 = 60, so 4w = 50, and \( w = 12.5 \).
Length = 12.5 + 5 = 17.5 cm.
Dimensions: 12.5 cm by 17.5 cm.
#### 12.5, 17.5
Circumference = \( 2\pi r = 31.4 \).
Solve for radius \( r \): \( r = 31.4 / (2\pi) = 5 \) meters.