amc theatres fashion valley 18

AMC AMC MAA6000 30 2007.
AMC AMC12IBA-level amc.
AMC .
AMC20201029 +AMCAMC .
AMC .
2AMCAMC AMC 19992004.
AMCAMC8AIME~AMCAMC .
AMC8 pre-AMCAMC .
AMCAMCAMCAMCAMC.
AMC 8AMC 10AMC 12~~ AMC 8 AMC 10 .

AMC AMC MAA6000 30 2007.
AMC AMC12IBA-level amc.
AMC .
AMC20201029 +AMCAMC .
AMC .
2AMCAMC AMC 19992004.
AMCAMC8AIME~AMCAMC .
AMC8 pre-AMCAMC .
AMCAMCAMCAMCAMC.
AMC 8AMC 10AMC 12~~ AMC 8 AMC 10 .
Let \( a \) and \( b \) be complex numbers such that \( a + b = 4 \) and \( a^2 + b^2 = 10 \). Find \( |a - b| \).
\( a + b = 4 \)
\( a^2 + b^2 = 10 \)
We use the identity:
Substitute:
4^2 = 10 + 2ab \Rightarrow 16 = 10 + 2ab \Rightarrow 2ab = 6 \Rightarrow ab = 3
Now compute \( |a - b| \). Note:
|a - b|^2 = (a - b)(\overline{a} - \overline{b}) = |a|^2 - a\overline{b} - \overline{a}b + |b|^2
But better to use algebra:
|a - b|^2 = (a - b)^2 \quad ext{if real, but not necessarily.}