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/ #### 11,616
#### 11,616
February 22, 2026
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Where \( P = 10,000 \), \( r = 0.05 \), \( n = 4 \), and \( t = 3 \):
\[ A = 10,000 \left(1.0125\right)^{12} \]
\[ A \approx 10,000 \times 1.1616 = \$11,616 \]
A rocket is launched vertically with an initial velocity of 50 m/s. How long will it take to reach its peak height? (Assume \( g = 9.8 \, \text{m/s}^2 \))
Use the formula for time to reach peak height:
\[ t = \frac{v}{g} \]
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