11×17=187 → 1+8+7=16 → no

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• 11×14=154 → 1+5+4=10 → no
• 11×15=165 → 1+6+5=12 → not div by 9
• 11×16=176 → 1+7+6=14 → no
• 11×18=198 → 1+9+8=18 → divisible by 9 → yes
• So the smallest multiple of 11 in [100,199] divisible by 9 is 198.
• Therefore, the smallest possible batch size that allows full utilization (i.e., divides a valid dataset size) is $ oxed{198} $.

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