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/ = 105 + (n - 1) \times 7
= 105 + (n - 1) \times 7
February 22, 2026
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This is an arithmetic sequence with first term \(a = 105\), common difference \(d = 7\), and last term \(l = 994\).
The number of terms \(n\) is given by:
l = a + (n - 1)d
- 105 = (n - 1) \times 7
= (n - 1) \times 7
n - 1 = \frac{889}{7} = 127
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