#### 0.021
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- Increase over 50 days = \( 0.002 \times \frac{50}{10} = 0.01 \).
- Add this to the initial ratio:
- \( 0.011 + 0.01 = 0.021 \).
- A remediation process removes 20% of toxic chemicals each week from a contaminated pool that initially holds 5,000 liters. How much chemical remains after 6 weeks?
- \( \text{Remaining chemicals} = 5,000 \times (1 - 0.20)^6 \).
- Calculate \( (1 - 0.20)^6 = 0.80^6 \).
