\( x = 0 \): \( 9(0) + 25y^2 = 225 \Rightarrow y^2 = 9 \Rightarrow y = \pm 3 \) → 2 points

["Understanding the Solution: ( x = 0 ) in the Equation ( 9(0) + 25y^2 = 225 )", "In algebra, solving equations step-by-step is essential for finding accurate solutions—especially in problems involving variables and constants. One clear example illustrates the significance of substituting values and simplifying expressions correctly.", "Given the equation:\n[ 9(0) + 25y^2 = 225 ]", "First, simplify the term ( 9(0) ):\n[ 0 + 25y^2 = 225 ]\n[ 25y^2 = 225 ]", "Next, isolate ( y^2 ) by dividing both sides by 25:\n[ y^2 = \frac{225}{25} ]\n[ y^2 = 9 ]", "Now, solve for ( y ) by taking the square root of both sides:\n[ y = \pm \sqrt{9} ]\n[ y = \pm 3 ]", "This means the equation has two real solutions: ( y = 3 ) and ( y = -3 ). The solutions reflect symmetry about the origin due to the squaring operation, a key concept in quadratic relationships.", "In summary, solving ( x = 0 ) in this equation demonstrates clear algebraic manipulation and highlights the two-point nature of solutions for ( y ). Proper stepwise solving ensures clarity and accuracy—critical skills for mastering algebraic problems. Whether tackling equations in academic study or real-world applications, understanding each transformation step enhances problem-solving confidence."]